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TABLE 9-6
The quality control engineer for a furniture manufacturer is interested in the mean amount of force necessary to produce cracks in stressed oak furniture.She performs a two-tail test of the null hypothesis that the mean for the stressed oak furniture is 650.The calculated value of the Z test statistic is a positive number that leads to a p-value of 0.080 for the test.
-True or False: Referring to Table 9-6,suppose the engineer had decided that the alternative hypothesis to test was that the mean was greater than 650.Then if the test is performed with a level of significance of 0.05,the null hypothesis would be rejected.
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