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Given the Half-Reactions And Ered \mathrm{E}_{\mathrm{red}}^{\circ} Values in the Table Below, Determine Which Species Is the Table

question 7

Multiple Choice

Given the half-reactions and Ered \mathrm{E}_{\mathrm{red}}^{\circ} values in the table below, determine which species is the best oxidizing agent.
MnO4(aq) +8H+(aq) +5eMn2+(aq) +4H2O(l) Ered=+1.512 V4H+(aq) +NO3(aq) +3eNO(g) +2H2O(l) Ered=+0.964 VFe3+(aq) +eFe2+(s) Ered=+0.771 V2H+(aq) +2eH2(g) Ered =0.000 V\begin{array}{ll}\mathrm{MnO}_{4}-(a q) +8 \mathrm{H}^{+}(a q) +5 e^{-} \rightarrow \mathrm{Mn}^{2+}(a q) +4 \mathrm{H}_{2} \mathrm{O}(l) & \mathrm{E}_{\mathrm{red}=+1.512 \mathrm{~V}}^{\circ} \\4 \mathrm{H}^{+}(a q) +\mathrm{NO}_{3}-(a q) +3 e^{-} \rightarrow \mathrm{NO}(g) +2 \mathrm{H}_{2} \mathrm{O}(l) & \mathrm{E}_{\mathrm{red}=+0.964 \mathrm{~V}}^{\circ} \\\mathrm{Fe}^{3+}(a q) +e-\rightarrow \mathrm{Fe}^{2+}(s) & \mathrm{E}_{\mathrm{red}}^{\circ}=+0.771 \mathrm{~V} \\2 \mathrm{H}^{+}(a q) +2 e^{-} \rightarrow \mathrm{H}_{2}(g) & \mathrm{E}_{\text {red }}^{\circ}=0.000 \mathrm{~V}\end{array}


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