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Calculate E for the following electrochemical cell at 25°C,
Cu | Cu2+ (0.100 M) || Zn2+ (0.0750 M) | Zn
If E° (Cu2+) = +0.339 V and E° (Zn2+) = −0.762 V.(R = 8.31 J/K⋅mol,F = 96480 C/mol e−)
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