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Calculate E° for the Electrochemical Cell Below, Pb |PbCl2 |

question 46

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Calculate E° for the electrochemical cell below, Pb |PbCl2 | Cl- || Fe3+,Fe2+ | Pt Given the following reduction half-reactions.
Pb2+(aq) +2ePb(s) E=0.126 VPbCl2(s) +2ePb(s) +2Cl(aq) E=0.267 VFe3+(aq) +eFe2+(aq) E=+0.771 VFe2+(aq) +eFe(s) E=0.44 V\begin{array}{ll}\mathrm{Pb}^{2+}(a q) +2 e^{-} \rightarrow \mathrm{Pb}(s) & E^{\circ}=-0.126 \mathrm{~V} \\\mathrm{PbCl}_{2}(s) +2 e^{-} \rightarrow \mathrm{Pb}(s) +2 \mathrm{Cl}^{-}(a q) & E^{\circ}=-0.267 \mathrm{~V} \\\mathrm{Fe}^{3+}(a q) +e^{-} \rightarrow \mathrm{Fe}^{2+}(a q) & E^{\circ}=+0.771 \mathrm{~V} \\\mathrm{Fe}^{2+}(a q) +e^{-} \rightarrow \mathrm{Fe}(s) & E^{\circ}=-0.44 \mathrm{~V}\end{array}


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