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Determine the Equilibrium Constant for the Reaction HF(aq)+ NH3(aq) A) 12 × 10?8
B) 1

question 34

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Determine the equilibrium constant for the reaction HF(aq) + NH3(aq) ? F?(aq) + NH4+(aq)
Given the equilibrium constants for the following reactions.
HF(aq) +H2O(l) F(aq) +H3O(aq) Ka=6.9×104NH3(aq) +H2O(l) NH4+(aq) +OH(aq) Kb=1.8×1052H2OOH(aq) +H3O+(aq) KW=1.0×1014\begin{array}{ll}\mathrm{HF}(a q) +\mathrm{H}_{2} \mathrm{O}(l) \rightleftharpoons \mathrm{F}-(a q) +\mathrm{H}_{3} \mathrm{O}^{-}(a q) & K_{\mathrm{a}}=6.9 \times 10^{-4} \\\mathrm{NH}_{3}(a q) +\mathrm{H}_{2} \mathrm{O}(l) \rightleftharpoons \mathrm{NH}_{4}^{+}(a q) +\mathrm{OH}-(a q) & K_{\mathrm{b}}=1.8 \times 10^{-5} \\2 \mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{OH}-(a q) +\mathrm{H}_{3} \mathrm{O}^{+}(a q) & K_{\mathrm{W}}=1.0 \times 10^{-14}\end{array}


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