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The Reaction of Nitrogen with Hydrogen to Form Ammonia Is

question 32

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The reaction of nitrogen with hydrogen to form ammonia is thermodynamically favorable.
N2( g) +3H2( g) 2NH3( g) ΔH=92.2 kJ\mathrm{N}_{2}(\mathrm{~g}) +3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g}) \quad\quad\quad\quad\quad\quad\quad \Delta H^{\circ}=-92.2 \mathrm{~kJ} J
The equilibrium constant for this reaction is 6.0 × 105 at 298 K.At what temperature is the equilibrium constant equal to 1.0 × 103? (R = 8.31 J/mol⋅K)


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