The Mass of a Single Atom of Chlorine Atom Is

question 26

Multiple Choice

The mass of a single atom of chlorine atom is 5.887 × 10?²³ grams.Which is a correct method for determining the molar mass of elemental chlorine,Cl₂?

• A) \(\frac{5.887 \times 10^{-23} \mathrm{~g}}{1 \text { atom Cl }}\left(\frac{1 \text { atom }}{6.022 \times 10^{23} \text { mole }}\right)\left(\frac{1 \mathrm{~mole} \mathrm{~Cl}_{2}}{2 \mathrm{~mole} \mathrm{~Cl}}\right)\)
• B) \(\frac{5.887 \times 10^{-23} \mathrm{~g}}{1 \text { atom } \mathrm{Cl}}\left(\frac{6.022 \times 10^{23} \text { atoms }}{1 \mathrm{~mole}}\right)\left(\frac{2 \mathrm{~mole} \mathrm{Cl}}{1 \mathrm{~mole} \mathrm{Cl}_{2}}\right)\)
• C) \(\frac{5.887 \times 10^{-23} \mathrm{~g}}{1 \text { atom Cl }}\left(\frac{1 \text { atom }}{6.022 \times 10^{23} \mathrm{~mole}}\right)\left(\frac{2 \mathrm{~mole} \mathrm{Cl}}{1 \mathrm{~mole} \mathrm{Cl}_{2}}\right)\)
• D) \(\frac{1 \text { atom Cl }}{5.887 \times 10^{-23} \mathrm{~g}}\left(\frac{6.022 \times 10^{23} \mathrm{~mole}}{1 \text { atom }}\right)\left(\frac{1 \mathrm{~mole} \mathrm{Cl}_{2}}{2 \mathrm{~mole} \mathrm{Cl}}\right)\)
• E) \(\frac{5.887 \times 10^{-23} \mathrm{~g}}{1 \text { atom } \mathrm{Cl}}\left(\frac{6.022 \times 10^{23} \text { atoms }}{1 \mathrm{~mole}}\right)\left(\frac{1 \mathrm{~mole} \mathrm{Cl}_{2}}{2 \mathrm{~mole} \mathrm{Cl}}\right)\)

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