Which Is a Correct Method for Calculating the Moles of Calcium

question 41

Multiple Choice

Which is a correct method for calculating the moles of calcium carbonate present in 132 grams of calcium carbonate?

• A) \(132 \mathrm{~g} \mathrm{CaCO}_{3}\left(\frac{6.022 \times 10^{23} \text { atoms }}{1 \mathrm{~mol}}\right)\left(\frac{100.1 \mathrm{~mol}}{1 \mathrm{~g}}\right)\)
• B) \(132 \mathrm{~g} \mathrm{CaCO}_{3}\left(\frac{1 \mathrm{~mol}}{100.1 \mathrm{~g}}\right)\)
• C) \(132 \mathrm{~g} \mathrm{CaCO}_{3}\left(\frac{100.1 \mathrm{~g}}{1 \mathrm{~mol}}\right)\)
• D) \(132 \mathrm{~g} \mathrm{CaCO}_{3}\left(\frac{100.1 \mathrm{~mol}}{1 \mathrm{~g}}\right)\)
• E) none of the above

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