Which Method Is Correct for Converting Kelvin to Celsius?
A) $\mathrm{T}\left({ }^{\circ} \mathrm{C}\right)=\left(\frac{5^{\circ} \mathrm{C}}{9 \mathrm{~K}}\right) \mathrm{T}(\mathrm{K})+32$

question 27

Multiple Choice

Which method is correct for converting kelvin to Celsius?

• A) \(\mathrm{T}\left({ }^{\circ} \mathrm{C}\right)=\left(\frac{5^{\circ} \mathrm{C}}{9 \mathrm{~K}}\right) \mathrm{T}(\mathrm{K})+32\)
• B) \(\mathrm{T}\left({ }^{\circ} \mathrm{C}\right)=\left(\frac{9^{\circ} \mathrm{C}}{5 \mathrm{~K}}\right) \mathrm{T}(\mathrm{K})+273.15\)
• C) \(\mathrm{T}\left({ }^{\circ} \mathrm{C}\right)=\frac{5^{\circ} \mathrm{C}}{9 \mathrm{~K}}(\mathrm{~T}(\mathrm{~K})-273.15)\)
• D) \(\mathrm{T}\left({ }^{\circ} \mathrm{C}\right)=\frac{1^{\circ} \mathrm{C}}{1 \mathrm{~K}}(\mathrm{~T}(\mathrm{~K})-273.15)\)
• E) \(\mathrm{T}\left({ }^{\circ} \mathrm{C}\right)=\frac{1^{\circ} \mathrm{C}}{1 \mathrm{~K}}(\mathrm{~T}(\mathrm{~K})+273.15)\)

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