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How Many Milliliters of 1

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How many milliliters of 1.58 M HCl are needed to react completely with 23.2 g of NaHCO3 ( How many milliliters of 1.58 M HCl are needed to react completely with 23.2 g of NaHCO<sub>3</sub> (   = 84.02 g/mol) ? HCl(aq)  + NaHCO<sub>3</sub>(s)  → NaCl(s)  + H<sub>2</sub>O(l)  + CO<sub>2</sub>(g)  A)  638 mL B)  572 mL C)  536 mL D)  276 mL E)  175 mL = 84.02 g/mol) ? HCl(aq) + NaHCO3(s) → NaCl(s) + H2O(l) + CO2(g)


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