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Determine the standard enthalpy of formation of Fe2O3(s) given the thermochemical equations below. Fe(s) + 3 H2O( ) → Fe(OH) 3(s) + 3/2 H2(g)
ΔrH° = +160.9 kJ/mol-rxn
H2(g) + 1/2 O2(g) → H2O( )
ΔrH° = -285.8 kJ/mol-rxn
Fe2O3(s) + 3 H2O( ) → 2 Fe(OH) 3(s)
ΔrH° = +288.6 kJ/mol-rxn
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