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One step in the isolation of pure rhodium metal (Rh) is the precipitation of rhodium(III) hydroxide from a solution containing rhodium(III) sulfate according to the following balanced chemical equation: Rh2(SO4) 3(aq) + 6NaOH(aq) → 2Rh(OH) 3(s) + 3Na2SO4(aq)
If 3.10 g of rhodium(III) sulfate reacts with excess sodium hydroxide,what mass of rhodium(III) hydroxide may be produced?
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