2 Al(s)+ 6 HCl(aq)→ 2 AlCl₃(aq)+ 3 H₂(g) According to the Equation

question 64

Multiple Choice

2 Al(s) + 6 HCl(aq) → 2 AlCl₃(aq) + 3 H₂(g) According to the equation above,what mass of aluminum is needed to completely react with 2.98 mol of hydrochloric acid?

• A) 241 g
• B) 36.3 g
• C) 26.8 g
• D) 2.98 g
• E) 80.4 g

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