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Hydrogen Iodide Decomposes at 800 K Via a Second-Order Process

question 37

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Hydrogen iodide decomposes at 800 K via a second-order process to produce hydrogen and iodine according to the following chemical equation:
2 HI(g) → H2(g) + I2(g)
At 800 K it takes 142 seconds for the initial concentration of HI to decrease from 6.75 × 10-2 mol L-1 to 3.50 × 10-2 mol L-1.What is the rate constant for the reaction at this temperature?


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