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When 50.0 mL of 0.400 mol L-1 Ca(NO3) 2 is added to 50.0 mL of 0.800 mol L-1 NaF, CaF2 precipitates, as shown in the net ionic equation below. The initial temperature of both solutions is 24.0 °C. Assuming that the reaction goes to completion, and that the resulting solution has a mass of 100.00 g and a specific heat of 4.18 J When 50.0 mL of 0.400 mol L<sup>-1</sup> Ca(NO<sub>3</sub>) <sub>2</sub> is added to 50.0 mL of 0.800 mol L<sup>-1</sup> NaF, CaF<sub>2</sub> precipitates, as shown in the net ionic equation below. The initial temperature of both solutions is 24.0 °C. Assuming that the reaction goes to completion, and that the resulting solution has a mass of 100.00 g and a specific heat of 4.18 J     , calculate the final temperature of the solution. Ca<sup>2+</sup>(aq)  + 2F<sup>-</sup>(aq)  → CaF<sub>2</sub>(s)    H = -11.5 kJ A)  23.45 °C B)  24.55 °C C)  25.10 °C D)  25.65 °C When 50.0 mL of 0.400 mol L<sup>-1</sup> Ca(NO<sub>3</sub>) <sub>2</sub> is added to 50.0 mL of 0.800 mol L<sup>-1</sup> NaF, CaF<sub>2</sub> precipitates, as shown in the net ionic equation below. The initial temperature of both solutions is 24.0 °C. Assuming that the reaction goes to completion, and that the resulting solution has a mass of 100.00 g and a specific heat of 4.18 J     , calculate the final temperature of the solution. Ca<sup>2+</sup>(aq)  + 2F<sup>-</sup>(aq)  → CaF<sub>2</sub>(s)    H = -11.5 kJ A)  23.45 °C B)  24.55 °C C)  25.10 °C D)  25.65 °C , calculate the final temperature of the solution. Ca2+(aq) + 2F-(aq) → CaF2(s) When 50.0 mL of 0.400 mol L<sup>-1</sup> Ca(NO<sub>3</sub>) <sub>2</sub> is added to 50.0 mL of 0.800 mol L<sup>-1</sup> NaF, CaF<sub>2</sub> precipitates, as shown in the net ionic equation below. The initial temperature of both solutions is 24.0 °C. Assuming that the reaction goes to completion, and that the resulting solution has a mass of 100.00 g and a specific heat of 4.18 J     , calculate the final temperature of the solution. Ca<sup>2+</sup>(aq)  + 2F<sup>-</sup>(aq)  → CaF<sub>2</sub>(s)    H = -11.5 kJ A)  23.45 °C B)  24.55 °C C)  25.10 °C D)  25.65 °C H = -11.5 kJ


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