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According to the following reaction, what amount of Al2S3 remains when 20.00 g of Al2S3 and 2.00 g of H2O are reacted? A few of the molar masses are as follows:
Al2S3 = 150.17 g mol-1, H2O = 18.02 g mol-1. Al2S3(s) + 6H2O(l) → 2Al(OH) 3(s) + 3H2S(g)
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