Using the Born- Haber Cycle, the OH_f° of KBr Is

question 112

Multiple Choice

Using the Born- Haber cycle, the OH_f° of KBr is equal to _ _.

• A) OH_f°[K (g)] + OH_f°[Br (g)] - I₁ - E(Br) + OH_lattice
• B) OH_f°[K (g)] + OH_f°[Br (g)] + I₁(K) + E(Br) + OH_lattice
• C) OH_f°[K (g)] - OH_f°[Br (g)] + I₁(K) - E(Br) + OH_lattice
• D) OH_f°[K (g)] + OH_f°[Br (g)] + I₁(K) + E(Br) - OH_lattice
• E) OH_f°[K (g)] - OH_f°[Br (g)] - I₁(K) - E(Br) - OH_lattice

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