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The Reaction of 50 ML of Cl2 gas with 50

question 141

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The reaction of 50 mL of Cl2 gas with 50 mL of CH4 gas via the equation:
Cl2 (g) + CH4 (g) - HCl (g) + CH3Cl (g)
Will produce a total of mL of products if pressure and temperature are kept constant.


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