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Calculate the Value of the Reaction Quotient, Q, for the Voltaic

question 6

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Calculate the value of the reaction quotient, Q, for the voltaic cell constructed from the following two half-reactions when the Zn2+ion concentration is 0.0110 M and the Ag+ ion concentration is 1.27 M?
Zn2+(aq) +2e\mathrm { Zn } ^ { 2 + } ( \mathrm { aq } ) + 2 \mathrm { e } ^ { - } ? Zn(s) ;E=0.76 V\mathrm { Zn } ( \mathrm { s } ) ; E ^ { \circ } = - 0.76 \mathrm {~V} Ag+(aq) +e\mathrm { Ag } ^ { + } ( \mathrm { aq } ) + \mathrm { e } ^ { - } ? Ag(s) ;E=0.80 V\mathrm { Ag } ( \mathrm { s } ) ; E ^ { \circ } = 0.80 \mathrm {~V}


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