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Calculate the cell potential at 25 °C for the following overall reaction. Zn2+(aq) + 2 Fe2+(aq) → Zn(s) + 2 Fe3+(aq)
[Zn2+] = 1.50 × 10-4 M,[Fe3+] = 0.0200 M,and [Fe2+] = 0.0100 M.The standard reduction potentials are as follows:
Zn2+(aq) + 2 e- → Zn(s)
E° = -0.763 V
Fe3+(aq) + e- → Fe2+(aq)
E° = +0.771 V
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