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What Is Ka at 25°C for the Following Equilibrium Given \rightleftharpoons

question 58

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What is Ka at 25°C for the following equilibrium given Kb (CH3NH2) = 4.4 × 10-4 at 25°C.? CH3NH3+(aq) + H2O(l) \rightleftharpoons CH3NH2(aq) + H3O+(aq)


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