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Using the Thermodynamic Data Below and a Value of -717

question 15

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Using the thermodynamic data below and a value of -717 kJ/mole for the lattice enthalpy for KCl, calculate the ionization energy of K.  Enthalpy of atomization of K+89 kJ/mol Enthalpy of formation of KCl(s) 437 kJ/mol Enthalpy of formation of Cl(g) +121 kJ/mol Electron attachment enthalpy of Cl(g) 349 kJ/mol\begin{array} { l l } \text { Enthalpy of atomization of } \mathrm { K } & + 89 \mathrm {~kJ} / \mathrm { mol } \\\text { Enthalpy of formation of } \mathrm { KCl } ( \mathrm { s } ) & - 437 \mathrm {~kJ} / \mathrm { mol } \\\text { Enthalpy of formation of } \mathrm { Cl } ( \mathrm { g } ) & + 121 \mathrm {~kJ} / \mathrm { mol } \\\text { Electron attachment enthalpy of } \mathrm { Cl } ( \mathrm { g } ) & - 349 \mathrm {~kJ} / \mathrm { mol }\end{array}


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