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According to the Reaction Given Below, the Standard Enthalpy Change

question 38

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According to the reaction given below, the standard enthalpy change for the combustion of 1 mole of propane is -2043.0 kJ.
C3H8(g) + 5 O2(g) ? 3 CO2(g) + 4 H2O(g)
Calculate ?fH° for propane based on the given standard molar enthalpies of formation.
 molecule ΔfH(kJ/ mol-rxn ) CO2( g) 393.5H2O(g) 241.8\begin{array} { l l } \text { molecule } & \Delta {}_f H ^ { \circ } ( \mathrm { kJ } / \text { mol-rxn } ) \\\hline \mathrm { CO } _ { 2 } ( \mathrm {~g} ) & - 393.5 \\\mathrm { H } _ { 2 } \mathrm { O } ( \mathrm { g } ) & - 241.8\end{array}


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