Which Method Is Correct for Converting Kelvin to Celsius?
A)

question 39

Multiple Choice

Which method is correct for converting kelvin to Celsius?

• A) \(\mathrm { T } \left( { } ^ { \circ } \mathrm { C } \right) = \left( \frac { 5 ^ { \circ } \mathrm { C } } { 9 \mathrm {~K} } \right) \mathrm { T } ( \mathrm { K } ) + 32\)
• B) \(\mathrm { T } \left( { } ^ { \circ } \mathrm { C } \right) = \left( \frac { 9 ^ { \circ } \mathrm { C } } { 5 \mathrm {~K} } \right) \mathrm { T } ( \mathrm { K } ) + 273.15\)
• C) \(\mathrm { T } \left( { } ^ { \circ } \mathrm { C } \right) = \frac { 5 ^ { \circ } \mathrm { C } } { 9 \mathrm {~K} } ( \mathrm {~T} ( \mathrm {~K} ) - 273.15 )\)
• D) \(\mathrm { T } \left( { } ^ { \circ } \mathrm { C } \right) = \frac { 1 ^ { \circ } \mathrm { C } } { 1 \mathrm {~K} } ( \mathrm {~T} ( \mathrm {~K} ) - 273.15 )\)
• E) \(\mathrm { T } \left( { } ^ { \circ } \mathrm { C } \right) = \frac { 1 ^ { \circ } \mathrm { C } } { 1 \mathrm {~K} } ( \mathrm {~T} ( \mathrm {~K} ) + 273.15 )\)

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