The Potential Energy of a 0

question 42

Multiple Choice

The potential energy of a 0.20-kg particle moving along the x axis is given by U(x) = (8.0 J/m²) x² − (2.0 J/m⁴) x⁴.When the particle is at x = 1.0 m the magnitude of its acceleration is:

• A)0 m/s²
• B)-8 m/s²
• C)8 m/s²
• D)-40 m/s²
• E)40 m/s²

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