The Potential Energy of a 0

question 4

Multiple Choice

The potential energy of a 0.20-kg particle moving along the x axis is given by U(x) =(8.0 J/m²) x² + (2.0 J/m⁴) x^4.
When the particle is at x = 1.0 m it is traveling in the positive x direction with a speed of 5.0 m/s.It next stops momentarily to turn around at x =

• A)0 m
• B)-1.1 m
• C)1.1 m
• D)-2.3 m
• E)2.3 m

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