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A Circular Loop of Diameter 10 Cm, Carrying a Current

question 38

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A circular loop of diameter 10 cm, carrying a current of 0.20 A, is placed inside a magnetic field A circular loop of diameter 10 cm, carrying a current of 0.20 A, is placed inside a magnetic field   = 0.30 T   . The normal to the loop is parallel to a unit vector   = -0.60   - 0.80   . Calculate the magnitude of the torque on the loop due to the magnetic field. A)  4.7 × 10<sup>-4</sup> N ∙ m B)  2.8 × 10<sup>-4</sup> N ∙ m C)  0.60 × 10<sup>-4</sup> N ∙ m D)  1.2 × 10<sup>-4</sup> N ∙ m E)  zero = 0.30 T A circular loop of diameter 10 cm, carrying a current of 0.20 A, is placed inside a magnetic field   = 0.30 T   . The normal to the loop is parallel to a unit vector   = -0.60   - 0.80   . Calculate the magnitude of the torque on the loop due to the magnetic field. A)  4.7 × 10<sup>-4</sup> N ∙ m B)  2.8 × 10<sup>-4</sup> N ∙ m C)  0.60 × 10<sup>-4</sup> N ∙ m D)  1.2 × 10<sup>-4</sup> N ∙ m E)  zero . The normal to the loop is parallel to a unit vector A circular loop of diameter 10 cm, carrying a current of 0.20 A, is placed inside a magnetic field   = 0.30 T   . The normal to the loop is parallel to a unit vector   = -0.60   - 0.80   . Calculate the magnitude of the torque on the loop due to the magnetic field. A)  4.7 × 10<sup>-4</sup> N ∙ m B)  2.8 × 10<sup>-4</sup> N ∙ m C)  0.60 × 10<sup>-4</sup> N ∙ m D)  1.2 × 10<sup>-4</sup> N ∙ m E)  zero = -0.60 A circular loop of diameter 10 cm, carrying a current of 0.20 A, is placed inside a magnetic field   = 0.30 T   . The normal to the loop is parallel to a unit vector   = -0.60   - 0.80   . Calculate the magnitude of the torque on the loop due to the magnetic field. A)  4.7 × 10<sup>-4</sup> N ∙ m B)  2.8 × 10<sup>-4</sup> N ∙ m C)  0.60 × 10<sup>-4</sup> N ∙ m D)  1.2 × 10<sup>-4</sup> N ∙ m E)  zero - 0.80 A circular loop of diameter 10 cm, carrying a current of 0.20 A, is placed inside a magnetic field   = 0.30 T   . The normal to the loop is parallel to a unit vector   = -0.60   - 0.80   . Calculate the magnitude of the torque on the loop due to the magnetic field. A)  4.7 × 10<sup>-4</sup> N ∙ m B)  2.8 × 10<sup>-4</sup> N ∙ m C)  0.60 × 10<sup>-4</sup> N ∙ m D)  1.2 × 10<sup>-4</sup> N ∙ m E)  zero . Calculate the magnitude of the torque on the loop due to the magnetic field.


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Accumulated net profits of a company not distributed as dividends but reinvested in the business or kept as a reserve.

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