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Assuming the Radius of Diatomic Molecules Is Approximately for What

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Assuming the radius of diatomic molecules is approximately Assuming the radius of diatomic molecules is approximately   for what pressure will the mean free path in room-temperature (20°C)  nitrogen be 4.6 m? The Boltzmann constant is 1.38 × 10<sup>-23</sup> J/K, Avogadro's number is 6.02 × 10<sup>23</sup> molecules/mole, and the ideal gas constant is   = 0.0821 L ∙ atm/mol ∙ K. A)  4.9 × 10<sup>-8</sup><sub> atm</sub> B)  6.9 × 10<sup>-8</sup><sub> atm</sub> C)  1.5 × 10<sup>-7</sup><sub> atm</sub> D)  2.2 × 10<sup>-7</sup><sub> atm</sub> for what pressure will the mean free path in room-temperature (20°C) nitrogen be 4.6 m? The Boltzmann constant is 1.38 × 10-23 J/K, Avogadro's number is 6.02 × 1023 molecules/mole, and the ideal gas constant is Assuming the radius of diatomic molecules is approximately   for what pressure will the mean free path in room-temperature (20°C)  nitrogen be 4.6 m? The Boltzmann constant is 1.38 × 10<sup>-23</sup> J/K, Avogadro's number is 6.02 × 10<sup>23</sup> molecules/mole, and the ideal gas constant is   = 0.0821 L ∙ atm/mol ∙ K. A)  4.9 × 10<sup>-8</sup><sub> atm</sub> B)  6.9 × 10<sup>-8</sup><sub> atm</sub> C)  1.5 × 10<sup>-7</sup><sub> atm</sub> D)  2.2 × 10<sup>-7</sup><sub> atm</sub> = 0.0821 L ∙ atm/mol ∙ K.


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