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A Block of Mass M = 9 0.50 m/s0.50 \mathrm {~m} / \mathrm { s } \text {, }

question 101

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A block of mass m = 9.0 kg and speed V and is behind a block of mass M = 27 kg and speed of 0.50 m/s0.50 \mathrm {~m} / \mathrm { s } \text {, } as shown int the figure. The surface is frictionless, and the blocks suddenly collide and couple. After the collision, the blocks have a common speed of 0.90 m/s. How much kinetic energy of the blocks is lost due to the collision?  A block of mass m = 9.0 kg and speed V and is behind a block of mass M = 27 kg and speed of  0.50 \mathrm {~m} / \mathrm { s } \text {, }  as shown int the figure. The surface is frictionless, and the blocks suddenly collide and couple. After the collision, the blocks have a common speed of 0.90 m/s. How much kinetic energy of the blocks is lost due to the collision?   A) 8.6 J B) 2.0 J C) 4.6 J D) 11 J E) 31 J


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