A Man Has Either an AaBB or AABb Genotype with Equal

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Examlex · Accepted Answer

The Answer is To determine the overall probability that the man will produce an Ab gamete, we need to consider both possible genotypes (AaBB and AABb) and calculate the probability of an Ab gamete for each, then average them since he has an equal probability of having either genotype.

For the AaBB genotype:
- The probability of contributing an A allele from the Aa pair is 1/2 (since he can contribute either A or a).
- The probability of contributing a B allele from the BB pair is 1 (since both alleles are B, he can only contribute a B).

So, the probability of an Ab gamete from the AaBB genotype is 0, because he cannot produce an Ab gamete with this genotype (he can only produce AB or aB gametes).

For the AABb genotype:
- The probability of contributing an A allele from the AA pair is 1 (since both alleles are A, he can only contribute an A).
- The probability of contributing a b allele from the Bb pair is 1/2 (since he can contribute either B or b).

So, the probability of an Ab gamete from the AABb genotype is 1 * 1/2 = 1/2.

Now, we average the probabilities from both genotypes:

(Probability from AaBB + Probability from AABb) / 2
= (0 + 1/2) / 2
= 1/2 / 2
= 1/4

Therefore, the overall probability that the man will produce an Ab gamete is 1/4 or 25%.

A Man Has Either an AaBB or AABb Genotype with Equal

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