Programming
Write a Static Method Named LargerDigits That Accepts TwoHint: If You Are Building a Result Number, You May

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Programming 
Write a Static Method Named LargerDigits That Accepts TwoHint: If You Are Building a Result Number, You May

Examlex · Accepted Answer

The Answer is // count digits, use Math.pow to scale up; use if/else to compare
public static int largerDigits(int a, int b) {
int digits = 0;
int result = 0;
while (a != 0 && b != 0) {
if (a % 10 > b % 10) {
result += a % 10 * (int) Math.pow(10, digits);
} else {
result += b % 10 * (int) Math.pow(10, digits);
}
a = a / 10;
b = b / 10;
digits++;
}
return result;
}
// cumulative multiplier and Math.max
public static int largerDigits(int a, int b) {
int multiplier = 1;
int result = 0;
while (a != 0 && b != 0) {
int digit = Math.max(a % 10, b % 10);
result += digit * multiplier;
a = a / 10;
b = b / 10;
multiplier = multiplier * 10;
}
return result;
}
public static boolean containsBothDigits(int a, int b, int c) {
int count = 0;
while (a != 0) {
int digit = a % 10;
a = a / 10;
if (digit == b) {
count++;
b = -1; // so that it won't be counted twice
}
if (digit == c) {
count++;
c = -1; // so that it won't be counted twice
}
}
if (count == 2) {
return true;
} else {
return false;
}
}
public static boolean containsBothDigits(int a, int b, int c) {
boolean foundB = false, foundC = false;
while (a != 0) {
foundB = foundB || a % 10 == b;
foundC = foundC || a % 10 == c;
a /= 10;
}
return foundB && foundC;
}
public static boolean containsBothDigits(int a, int b, int c) {
return containsDigit(a, b) && containsDigit(a, c);
}
public static boolean containsDigit(int a, int b) {
while (a != 0) {
if (a % 10 == b) {
return true;
}
a = a / 10;
}
return false;
}

Programming Write a Static Method Named LargerDigits That Accepts Two

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Programming
Write a Static Method Named LargerDigits That Accepts Two