Find the Point (X, Y) on the Unit Circle That $t = \frac { 5 \pi } { 6 }$

question 38

Multiple Choice

Find the point (x, y) on the unit circle that corresponds to the real number t. $t = \frac { 5 \pi } { 6 }$

• A) \(t = \frac { 5 \pi } { 6 }\) corresponds to the point \(\left( \frac { 1 } { 2 } , - \frac { \sqrt { 3 } } { 2 } \right)\) .
• B) \(t = \frac { 5 \pi } { 6 }\) corresponds to the point \(\left( - \frac { \sqrt { 3 } } { 2 } , \frac { 1 } { 2 } \right)\) .
• C) \(t = \frac { 5 \pi } { 6 }\) corresponds to the point \(\left( - \frac { \sqrt { 3 } } { 2 } , - \frac { 1 } { 2 } \right)\) .
• D) \(t = \frac { 5 \pi } { 6 }\) corresponds to the point \(\left( \frac { \sqrt { 3 } } { 2 } , - \frac { 1 } { 2 } \right)\) .
• E) \(t = \frac { 5 \pi } { 6 }\) corresponds to the point \(\left( \frac { \sqrt { 3 } } { 2 } , \frac { 1 } { 2 } \right)\) .

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