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Use the Formula asinBθ+bcosBθ=a2+b2cos(BθC)a \sin B \theta + b \cos B \theta = \sqrt { a ^ { 2 } + b ^ { 2 } } \cos ( B \theta - C )

question 92

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Use the formula asinBθ+bcosBθ=a2+b2cos(BθC) a \sin B \theta + b \cos B \theta = \sqrt { a ^ { 2 } + b ^ { 2 } } \cos ( B \theta - C ) , where C=arctan(a/b) ,a=13,b=6,B=3C = \arctan ( a / b ) , a = 13 , b = 6 , B = 3 to rewrite the trigonometric expression in the following form.
y=a2+b2cos(BθC) y = \sqrt { a ^ { 2 } + b ^ { 2 } } \cos ( B \theta - C ) asinBθ+bcosBθa \sin B \theta + b \cos B \theta


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