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The Equation 2sin4t1=02 \sin 4 t - 1 = 0 Has Four Times the Number of Solutions in the Interval

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The equation 2sin4t1=02 \sin 4 t - 1 = 0 has four times the number of solutions in the interval [0, 2 π\pi ) as the equation 2sint1=02 \sin t - 1 = 0 .


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