Use the Trigonometric Substitution to Rewrite the Algebraic Expression as a Trigonometric

question 246

Multiple Choice

Use the trigonometric substitution to rewrite the algebraic expression as a trigonometric function of $\theta$ , where $0 < x < \frac { \pi } { 2 }$ . $\sqrt { 6 - x ^ { 2 } } , x = \sqrt { 6 } \sin \theta$

• A)6 sin \(\theta \)
• B) \(- \sqrt { 6 } \cos \theta\)
• C) \(\sqrt { 6 } \sin \theta\)
• D) \(\sqrt { 6 } \cos \theta\)
• E)6 cos \(\theta \)

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