Fourty Liters of a 40% Acid Solution Is Obtained by Mixing

question 207

Multiple Choice

Fourty liters of a 40% acid solution is obtained by mixing a 28% solution with a 50% solution.Write a system of equations in which one equation represents the amount of final mixture required and the other represents the percent of acid in the final mixture.Let x and y represent the amounts of the 28% and 50% solutions, respectively.

• A) \(\left\{ \begin{array} { l }
• x + y = 40 \\
• 0.28 x + 0.5 y = 40
• \end{array} \right.\)
• B) \(\left\{ \begin{array} { l }
• 0.28 x + 0.5 y = 40 \\
• x + y = 16
• \end{array} \right.\)
• C) \(\left\{ \begin{array} { l }
• x + y = 40 \\
• 0.28 x + 0.5 y = 16
• \end{array} \right.\).
• D) \(\left\{ \begin{array} { l }
• x + y = 40 \\
• 0.28 x + 0.5 y = 16
• \end{array} \right.\)
• E) \(\left\{ \begin{array} { l }
• 0.28 x + 0.5 y = 40 \\
• x + y = 16
• \end{array} \right.\).

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