Solve the System by the Method of Elimination and Check$\left\{ \begin{array} { l }
0.05 x - 0.03 y = 0.29 \
0.07 x + 0.02 y = 0.22
\end{array} \right.$

Question

Solve the System by the Method of Elimination and Check$\left\{ \begin{array} { l } 
0.05 x - 0.03 y = 0.29 \
0.07 x + 0.02 y = 0.22
\end{array} \right.$

Examlex · Accepted Answer

The Answer of Solve the System by the Method of Elimination and Check$\left\{ \begin{array} { l } 
0.05 x - 0.03 y = 0.29 \
0.07 x + 0.02 y = 0.22
\end{array} \right.$

Solve the System by the Method of Elimination and Check $\left\{ \begin{array} { l } 0.05 x - 0.03 y = 0.29 \\0.07 x + 0.02 y = 0.22\end{array} \right.$

Definitions:

Solve the System by the Method of Elimination and Check {0.05x−0.03y=0.290.07x+0.02y=0.22\left\{ \begin{array} { l } 0.05 x - 0.03 y = 0.29 \\0.07 x + 0.02 y = 0.22\end{array} \right.{0.05x−0.03y=0.290.07x+0.02y=0.22​

Definitions:

Solve the System by the Method of Elimination and Check $\left\{ \begin{array} { l } 0.05 x - 0.03 y = 0.29 \\0.07 x + 0.02 y = 0.22\end{array} \right.$