Find the Polar Equation of the Planet's Orbit and the Perihelion

question 423

Multiple Choice

Find the polar equation of the planet's orbit and the perihelion and aphelion distances.
Earth $a = 95.956 \times 10 ^ { 6 }$ miles $e = 0.0167$

• A) \(\frac { 0.9593 \times 10 ^ { 8 } } { 1 - 0.0167 \cos \theta }\) Perihelion distance: \(r = 9.4354 \times 10 ^ { 8 }\) Aphelion distance: \(r = 9.7558 \times 10 ^ { 8 }\)
• B) \(\frac { 0.9593 \times 10 ^ { 8 } } { 1 - 0.0167 \sin \theta }\) Perihelion distance: \(r = 9.7558 \times 10 ^ { 8 }\) Aphelion distance: \(r = 9.4354 \times 10 ^ { 8 }\)
• C) \(\frac { 0.0167 \times 10 ^ { 8 } } { 1 + 0.9593 \sin \theta }\) Perihelion distance: \(r = 9.4354 \times 10 ^ { 8 }\) Aphelion distance: \(r = 9.7558 \times 10 ^ { 8 }\)
• D) \(\frac { 0.9593 \times 10 ^ { 7 } } { 1 - 0.0167 \cos \theta }\) Perihelion distance: \(r = 9.7558 \times 10 ^ { 8 }\) Aphelion distance: \(r = 9.4354 \times 10 ^ { 8 }\)
• E) \(\frac { 0.9593 \times 10 ^ { 7 } } { 1 + 0.0167 \cos \theta }\) Perihelion distance: \(r = 9.4354 \times 10 ^ { 7 }\) Aphelion distance: \(r = 9.7558 \times 10 ^ { 7 }\)

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