Select the Correct Graph of the Polar Equation $r = 2 \csc \theta + 5$

question 546

Multiple Choice

Select the correct graph of the polar equation.Describe your viewing window. $r = 2 \csc \theta + 5$

• A) \(\begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 12 \\ X _ { \max } = 12 \\ X _ { s c l } = 2 \\ Y _ { \min } = - 12 \\ Y _ { \max } = 12 \\ Y _ { s c l } = 2 \end{array}\)
• B) \(\begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 12 \\ X _ { \max } = 12 \\ X _ { s c l } = 2 \\ Y _ { \min } = - 12 \\ Y _ { \max } = 12 \\ Y _ { s c l } = 2 \end{array}\)
• C) \(\begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 12 \\ X _ { \max } = 12 \\ X _ { s c l } = 2 \\ Y _ { \min } = - 12 \\ Y _ { \max } = 12 \\ Y _ { s c l } = 2 \end{array}\)
• D) \(\begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 12 \\ X _ { \max } = 12 \\ X _ { s c l } = 2 \\ Y _ { \min } = - 12 \\ Y _ { \max } = 12 \\ Y _ { s c l } = 2 \end{array}\)
• E) \(\begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 12 \\ X _ { \max } = 12 \\ X _ { s c l } = 2 \\ Y _ { \min } = - 12 \\ Y _ { \max } = 12 \\ Y _ { s c l } = 2 \end{array}\)

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