Use the Quadratic Formula to Solve For $y$ $x ^ { 2 } + 12 x y + 36 y ^ { 2 } - 5 x - y - 3 = 0$

question 277

Multiple Choice

Use the Quadratic Formula to solve for $y$ . $x ^ { 2 } + 12 x y + 36 y ^ { 2 } - 5 x - y - 3 = 0$

• A) \(y = \frac { - ( 36 x + 1 ) \pm \sqrt { ( 36 x - 1 ) ^ { 2 } - 144 \left( x ^ { 2 } - 5 x - 3 \right) } } { 72 }\)
• B) \(y = \frac { - ( 12 x + 1 ) \pm \sqrt { ( 36 x + 1 ) ^ { 2 } - 144 \left( x ^ { 2 } + 5 x + 3 \right) } } { 72 }\)
• C) \(y = \frac { - ( 36 x - 1 ) \pm \sqrt { ( 36 x - 1 ) ^ { 2 } - 144 \left( x ^ { 2 } - 5 x + 3 \right) } } { 72 }\)
• D) \(y = \frac { ( 36 x - 1 ) \pm \sqrt { ( 36 x - 1 ) ^ { 2 } - 144 \left( x ^ { 2 } - 5 x - 3 \right) } } { 72 }\)
• E) \(y = \frac { - ( 12 x - 1 ) \pm \sqrt { ( 12 x - 1 ) ^ { 2 } - 144 \left( x ^ { 2 } - 5 x - 3 \right) } } { 72 }\)

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