Use the Quadratic Formula to Solve For $y$ $x ^ { 2 } + x y + 4 y ^ { 2 } + x + y - 4 = 0$

question 497

Multiple Choice

Use the Quadratic Formula to solve for $y$ . $x ^ { 2 } + x y + 4 y ^ { 2 } + x + y - 4 = 0$

• A) \(y = \frac { ( x + 1 ) \pm \sqrt { ( x - 1 ) ^ { 2 } - 8 \left( x ^ { 2 } - x + 4 \right) } } { 4 }\)
• B) \(y = \frac { - ( x + 1 ) \pm \sqrt { ( x + 1 ) ^ { 2 } - 8 \left( x ^ { 2 } + x + 4 \right) } } { 4 }\)
• C) \(y = \frac { - ( x + 1 ) \pm \sqrt { ( x + 1 ) ^ { 2 } - 8 \left( x ^ { 2 } + x - 4 \right) } } { 4 }\)
• D) \(y = \frac { ( x + 1 ) \pm \sqrt { ( x + 1 ) ^ { 2 } - 8 \left( x ^ { 2 } + x - 4 \right) } } { 4 }\)
• E) \(y = \frac { - ( x + 1 ) \pm \sqrt { ( x + 1 ) ^ { 2 } + 8 \left( x ^ { 2 } + x - 4 \right) } } { 4 }\)

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