Find the Standard Form of the Equation of the Ellipse $\frac { x ^ { 2 } } { 4 } + \frac { y ^ { 2 } } { 25 } = 0$

question 287

Multiple Choice

Find the standard form of the equation of the ellipse with the following graph.

• A) \(\frac { x ^ { 2 } } { 4 } + \frac { y ^ { 2 } } { 25 } = 0\) , \(\frac { x ^ { 2 } } { 36 } + \frac { y ^ { 2 } } { 4 } = 0\) , \(x ^ { 2 } + \frac { y ^ { 2 } } { 16 } = 0\)
• B) \(\frac { x ^ { 2 } } { 4 } + \frac { y ^ { 2 } } { 25 } = 100\) , \(\frac { x ^ { 2 } } { 36 } - \frac { y ^ { 2 } } { 4 } = 1\) , \(x ^ { 2 } - \frac { y ^ { 2 } } { 16 } = 1\)
• C) \(25 x ^ { 2 } + 4 y ^ { 2 } = 1\) , \(\frac { x ^ { 2 } } { 2 } - \frac { y ^ { 2 } } { 36 } = 1\) , \(\frac { x ^ { 2 } } { 16 } - y ^ { 2 } = 1\)
• D) \(\frac { x ^ { 2 } } { 4 } + \frac { y ^ { 2 } } { 25 } = 1\) , \(\frac { x ^ { 2 } } { 36 } + \frac { y ^ { 2 } } { 4 } = 1\) , \(x ^ { 2 } + \frac { y ^ { 2 } } { 16 } = 1\)
• E) \(\frac { x ^ { 2 } } { 25 } + \frac { y ^ { 2 } } { 4 } = 1\) , \(\frac { x ^ { 2 } } { 4 } + \frac { y ^ { 2 } } { 36 } = 1\) , \(\frac { x ^ { 2 } } { 16 } + y ^ { 2 } = 1\)

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