The Path of a Projectile Projected Horizontally with a Velocity $x ^ { 2 } = - \frac { v ^ { 2 } } { 16 } ( y - s )$

question 508

Multiple Choice

The path of a projectile projected horizontally with a velocity of v feet per second at a height of s feet, where the model for the path is $x ^ { 2 } = - \frac { v ^ { 2 } } { 16 } ( y - s )$ .In this model (in which air resistance is disregarded) , y is the height (in feet) of the projectile and x is the horizontal distance (in feet) the projectile travels.A ball is thrown from the top of a 150-foot tower with a velocity of 32 feet per second.Find the equation of the parabolic path.

• A) \(x ^ { 2 } = - 32 ( y - 150 )\)
• B) \(x ^ { 2 } = 64 ( y - 150 )\)
• C) \(x ^ { 2 } = 1406 ( y - 32 )\)
• D) \(x ^ { 2 } = - 1406 ( y - 32 )\)
• E) \(x ^ { 2 } = - 64 ( y - 150 )\)

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