Find U × V and Show That It Is Orthogonal $\mathbf { u } = ( 13,1,14 ) \quad \mathbf { v } = ( 12 , - 12 , - 1 )$

question 120

Multiple Choice

Find u × v and show that it is orthogonal to both u and v. $\mathbf { u } = ( 13,1,14 ) \quad \mathbf { v } = ( 12 , - 12 , - 1 )$

• A) \(\begin{array} { l }
• \mathbf { u } \times \mathbf { v } = ( 181,167 , - 167 ) \\
• ( \mathbf { u } \times \mathbf { v } ) \cdot \mathbf { u } = 0 \\
• ( \mathbf { u } \times \mathbf { v } ) \cdot \mathbf { v } = 0
• \end{array}\)
• B) \(\begin{array} { l }
• \mathbf { u } \times \mathbf { v } = ( 181,167 , - 168 ) \\
• ( \mathbf { u } \times \mathbf { v } ) \cdot \mathbf { u } \neq 0 \\
• ( \mathbf { u } \times \mathbf { v } ) \cdot \mathbf { v } \neq 0
• \end{array}\)
• C) \(\begin{array} { l }
• \mathbf { u } \times \mathbf { v } = ( 167,181,168 ) \\
• ( \mathbf { u } \times \mathbf { v } ) \cdot \mathbf { u } = 0 \\
• ( \mathbf { u } \times \mathbf { v } ) \cdot \mathbf { v } = 0
• \end{array}\)
• D) \(\begin{array} { l }
• \mathbf { u } \times \mathbf { v } = ( 167,181 , - 168 ) \\
• ( \mathbf { u } \times \mathbf { v } ) \cdot \mathbf { u } = 0 \\
• ( \mathbf { u } \times \mathbf { v } ) \cdot \mathbf { v } = 0
• \end{array}\)
• E) \(\begin{array} { l }
• \mathbf { u } \times \mathbf { v } = ( 167,181 , - 168 ) \\
• ( \mathbf { u } \times \mathbf { v } ) \cdot \mathbf { u } \neq 0 \\
• ( \mathbf { u } \times \mathbf { v } ) \cdot \mathbf { v } \neq 0
• \end{array}\)

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