Find the First Five Terms of the Sequence $\alpha _ { n } = \frac { n } { 2 n + 2 }$

question 231

Multiple Choice

Find the first five terms of the sequence. $\alpha _ { n } = \frac { n } { 2 n + 2 }$

• A) \(\alpha _ { 1 } = 4 , \alpha _ { 2 } = \frac { 1 } { 3 } , \alpha _ { 3 } = \frac { 3 } { 8 } , \alpha _ { 4 } = \frac { 2 } { 5 } , \alpha _ { 5 } = \frac { 5 } { 12 }\)
• B) \(\alpha _ { 1 } = 4 , \alpha _ { 2 } = \frac { 1 } { 3 } , \alpha _ { 3 } = \frac { 8 } { 3 } , \alpha _ { 4 } = \frac { 2 } { 5 } , \alpha _ { 5 } = \frac { 5 } { 12 }\)
• C) \(\alpha _ { 1 } = 4 , \alpha _ { 2 } = \frac { 1 } { 3 } , \alpha _ { 3 } = \frac { 3 } { 8 } , \alpha _ { 4 } = \frac { 2 } { 5 } , \alpha _ { 5 } = \frac { 12 } { 5 }\)
• D) \(\alpha _ { 1 } = \frac { 1 } { 4 } , \alpha _ { 2 } = \frac { 1 } { 3 } , \alpha _ { 3 } = \frac { 3 } { 8 } , \alpha _ { 4 } = \frac { 2 } { 5 } , \alpha _ { 5 } = \frac { 5 } { 12 }\)
• E) \(\alpha _ { 1 } = \frac { 1 } { 4 } , \alpha _ { 2 } = \frac { 1 } { 3 } , \alpha _ { 3 } = \frac { 8 } { 3 } , \alpha _ { 4 } = \frac { 2 } { 5 } , \alpha _ { 5 } = \frac { 12 } { 5 }\)

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