Find the Limit (If It Exists) $\lim _ { x \rightarrow \pi / 2 } \frac { 4 ( \cos x - 1 ) } { \sin x }$

question 148

Multiple Choice

Find the limit (if it exists) . $\lim _ { x \rightarrow \pi / 2 } \frac { 4 ( \cos x - 1 ) } { \sin x }$

• A) \(\lim _ { x \rightarrow \pi / 2 } \frac { 4 ( \cos x - 1 ) } { \sin x } = - 16\)
• B) \(\lim _ { x \rightarrow \pi / 2 } \frac { 4 ( \cos x - 1 ) } { \sin x } = - 4\)
• C) \(\lim _ { x \rightarrow \pi / 2 } \frac { 4 ( \cos x - 1 ) } { \sin x } = 20\)
• D) \(\lim _ { x \rightarrow \pi / 2 } \frac { 4 ( \cos x - 1 ) } { \sin x } = 16\)
• E) \(\lim _ { x \rightarrow \pi / 2 } \frac { 4 ( \cos x - 1 ) } { \sin x } = 4\)

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