Find the Limit by Direct Substitution $\lim _ { x \rightarrow 4 } \left( \frac { x - 1 } { x ^ { 2 } + 8 x + 9 } \right)$

question 99

Multiple Choice

Find the limit by direct substitution. $\lim _ { x \rightarrow 4 } \left( \frac { x - 1 } { x ^ { 2 } + 8 x + 9 } \right)$

• A) \(\lim _ { x \rightarrow 4 } \left( \frac { x - 1 } { x ^ { 2 } + 8 x + 9 } \right)\) = \(\frac { 1 } { 19 }\)
• B) \(\lim _ { x \rightarrow 4 } \left( \frac { x - 1 } { x ^ { 2 } + 8 x + 9 } \right)\) = -19
• C) \(\lim _ { x \rightarrow 4 } \left( \frac { x - 1 } { x ^ { 2 } + 8 x + 9 } \right)\) = \(\infty\)
• D) \(\lim _ { x \rightarrow 4 } \left( \frac { x - 1 } { x ^ { 2 } + 8 x + 9 } \right)\) = \(\frac { 19 } { 2 }\)
• E) \(\lim _ { x \rightarrow 4 } \left( \frac { x - 1 } { x ^ { 2 } + 8 x + 9 } \right)\) = \(- \frac { 2 } { 19 }\)

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