Find the Limit of the Sequence (If It Exists) $\alpha _ { n } = \frac { 4 n ^ { 2 } + 1 } { 2 n }$

question 191

Multiple Choice

Find the limit of the sequence (if it exists) . $\alpha _ { n } = \frac { 4 n ^ { 2 } + 1 } { 2 n }$

• A) \(\lim_ { n \rightarrow \infty } \alpha _ { n } = - 4\)
• B) \(\lim _ { n \rightarrow \infty } \alpha _ { n } = \frac { 1 } { 2 }\)
• C) \(\lim _ { n \rightarrow \infty }\alpha _ { n } = 4\)
• D) \(\lim_ { n \rightarrow \infty } \alpha _ { n } = 0\)
• E) \(\lim_ { n \rightarrow \infty } a _ { n } = \infty\)

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