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TABLE 14-11
a Logistic Regression Model Was Estimated

question 95

Multiple Choice

TABLE 14-11
A logistic regression model was estimated in order to predict the probability that a randomly chosen university or college would be a private university using information on average total Scholastic Aptitude Test score (SAT) at the university or college, the room and board expense measured in thousands of dollars (Room/Brd) , and whether the TOEFL criterion is at least 550 (Toefl550 = 1 if yes, 0 otherwise.) The dependent variable, Y, is school type (Type = 1 if private and 0 otherwise) .

Logistic Regression Table
 Odds  95: CI  Predictor  Coef  SE Coef Z P  Ratio  Lower  Upper  Constant 27.1186.6964.050.000 SAT 0.0150.0046663.170.0021.011.011.02 Toefl550 0.3900.95380.410.6820.680.104.39 Room/Brd 2.0780.50764.090.0007.992.9521.60\begin{array}{lrrrrrrr} & & & && \text { Odds } & \text { 95: CI } \\\text { Predictor } & {\text { Coef }} & \text { SE Coef } & Z &{\text { P }} & \text { Ratio } & \text { Lower } & \text { Upper } \\\text { Constant } &-27.118&6 .696& -4.05 & 0.000 & & & \\\text { SAT } & 0.015 & 0.004666 & 3.17 & 0.002 & 1.01 & 1.01 & 1.02 \\\text { Toefl550 } & -0.390 & 0.9538 & -0.41 & 0.682 & 0.68 & 0.10 & 4.39 \\\text { Room/Brd } & 2.078 & 0.5076 & 4.09 & 0.000 & 7.99 & 2.95 & 21.60\end{array}

Log-Likelihood = -21.883
Test that all slopes are zero: G = 62.083, DF = 3, P-Value = 0.000
Goodness-of-Fit Tests

 Method  Chi-Square  DF  P  Pearson 143.551760.000 Deviance 43.767760.999 Hosmer-Lemeshow 15.73180.046 \begin{array}{lrcr}\text { Method } & \text { Chi-Square } & \text { DF } & \text { P } \\ \text { Pearson } & 143.551 & 76 & 0.000 \\ \text { Deviance } & 43.767 & 76 & 0.999 \\ \text { Hosmer-Lemeshow } & 15.731 & 8 & 0.046\end{array}

-Referring to Table 14-11, which of the following is the correct interpretation for the Tofel500 slope coefficient?


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A chemical element with symbol C, capable of forming many compounds including carbon dioxide and organic molecules.

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