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TABLE 14-17
the Marketing Manager for a Nationally

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TABLE 14-17
The marketing manager for a nationally franchised lawn service company would like to study the characteristics that differentiate home owners who do and do not have a lawn service. A random sample of 30 home owners located in a suburban area near a large city was selected; 15 did not have a lawn service (code 0) and 15 had a lawn service (code 1). Additional information available concerning these 30 home owners includes family income (Income, in thousands of dollars), lawn size (Lawn Size, in thousands of square feet), attitude toward outdoor recreational activities (Attitude 0 = unfavorable, 1
= favorable), number of teenagers in the household (Teenager), and age of the head of the household (Age).
The Minitab output is given below:
 Odds  95 % CI Predictor Coef  SE Coef  Z P Ratio LowerUpper Constant 70.4947.221.490.135Income 0.28680.15231.880.0601.330.991.80Lawn Size1.06470.74721.420.1542.900.6712.54Attitude12.7449.4551.350.1780.000.00326.06Teenager0.2001.0610.190.8500.820.106.56Age1.07920.87831.230.2192.940.5316.45\begin{array}{lccccccrr} & & & & \text { Odds } & \text { 95 \% CI } \\\text {Predictor }& \text {Coef }&\text { SE Coef }&\text { Z }& \text {P} &\text { Ratio} &\text { Lower} & \text {Upper }\\\text {Constant }& -70.49 & 47.22 & -1.49 & 0.135 & & & \\\text {Income }& 0.2868 & 0.1523 & 1.88 & 0.060 & 1.33 & 0.99 & 1.80 \\\text {Lawn Size} & 1.0647 & 0.7472 & 1.42 & 0.154 & 2.90 & 0.67 & 12.54 \\\text {Attitude} & -12.744 & 9.455 & -1.35 & 0.178 & 0.00 & 0.00 & 326.06 \\\text {Teenager} & -0.200 & 1.061 & -0.19 & 0.850 & 0.82 & 0.10 & 6.56 \\\text {Age} & 1.0792 & 0.8783 & 1.23 & 0.219 & 2.94 & 0.53 & 16.45\end{array}

Log-Likelihood = -4.890
Test that all slopes are zero: G = 31.808, DF = 5, P-Value = 0.000

Goodness-of-Fit Tests
 Method  Chi-Square  DF  P  Pearson 9.313240.997 Deviance 9.780240.995 Hosmer-Lemeshow 0.57181.000 \begin{array}{lrrr}\text { Method } & \text { Chi-Square } & \text { DF } & \text { P } \\ \text { Pearson } & 9.313 & 24 & 0.997 \\ \text { Deviance } & 9.780 & 24 & 0.995 \\ \text { Hosmer-Lemeshow } & 0.571 & 8 & 1.000\end{array}

-Referring to Table 14-17, what is the p-value of the test statistic when testing whether Income makes a significant contribution to the model in the presence of the other independent variables?


Definitions:

Sedimentary Unit

A sedimentary unit is a distinct layer of sedimentary rock with identifiable characteristics and depositional history, making it recognizable and distinguishable from other layers.

Intrusion

The forced entry of molten rock into or between other rock formations underground.

Shear Zone

A region of the Earth's crust where rocks have been subjected to differential stress causing them to deform via shearing.

Pluton

A body of intrusive igneous rock that crystallized from magma cooling below the Earth's surface; can range in size from small to massive.

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